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Temka [501]
2 years ago
12

PLEASE READ! HELPFUL INFORMATION

Mathematics
1 answer:
Volgvan2 years ago
7 0

Answer:

u kind of forgot the attachment bestie

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Hello I need Help with this question ASAP PLS.
Korolek [52]

Answer:

$0.80

Step-by-step explanation:

Find the unit rate

1 apple costs ?

1.20/6 = cost of 1 apple

1 apple = $0.20

4 apples = $0.20 * 4

4 apples = $0.80

6 0
2 years ago
Read 2 more answers
Please can anyone help what is AC
Nesterboy [21]

The answer is C.

You need you use Pythagoras theorem 2 times to have 2 equations with the same sides i.e. for example a2 + b2 = 81 and a2 - b2 = 9.

You can do it as you have different triangles but with the same sides.

7 0
3 years ago
3. To buy a car, Jessica borrowed $15,000 for 3
elena55 [62]
A)15000 x (9 : 100) x 3 = 4050
B) 15000 + 4050 = 19050

I hope it is correct ❤️
7 0
2 years ago
An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh
Elenna [48]
Make a ratio: 
<span>
Make sure shadow is in same location on both fractions (either numerator or denominator) </span>

x/90=5/8 

Cross multiply: 

8x=90x5 
8x=450 
<span>
x=56.25 feet </span>

Therefore, the approximate height of the building to the nearest foot would be 56.25 feet.
<span>
That makes sense, too, because the woman's shadow is taller than she is, but is less than double her height. </span>The building shadow is taller than the building, but it's less than double the height of the building.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
8 0
3 years ago
Read 2 more answers
KLMN is a parallelogram,
Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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4 0
3 years ago
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