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2 years ago

Help please!!! This is a test and it's due is today. If anyone knows please help me I will mark as BRAINLIEST

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

6 0

Answer:

9)A. $280

B. $1120

10. 20%

11)A. $560

B.8560

12. $5950

Step-by-step explanation:

1400/5=280

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The FBI wants to determine the effectiveness of their 1010 Most Wanted list. To do so, they need to find out the fraction of peo

Murrr4er [49]

Answer:

The proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.

Step-by-step explanation:

Since the FBI wants to determine the effectiveness of their 1010 Most Wanted list, and to do so, they need to find out the fraction of people who appear on the list that are actually caught, supposing a sample of 517517 suspected criminals is drawn, and of these people, 211211 were captured, to estimate the proportion of people who were caught after being on the 1010 Most Wanted list using this data, the following calculation must be performed:

517,517 = 100

211,211 = X

211,211 x 100 / 517,517 = X

21,121,100 / 517,517 = X

40.81 = X

Therefore, the proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.

4 0

2 years ago

HALP PLeAASE i will give brainly ;D

a_sh-v [17]

Answer:

the total amount is £756.

Step-by-step explanation:

given, monthly charge =£16

rate per min of call= £13 per min(150free calls )

rate per texts= £15per text (150 free text)

now, total calls made =170calls

total text = 180 text

now, minimum charge for 150 calls is free

so, left calls = 20 calls

charge for 20 calls= 20×£13

therefore, the charge for 20 calls is £260

now, for text

no. of text = 182-150=32

now, charge for 32 text =£ 15× 32

therefore the charge of 32 text is £ 480.

now, total amount = monthly charge + extra call charge+ extra text charge.

or, total amount = £16+£260+£480

=£756

therefore, the total amount is £756.

hope it helps...

6 0

3 years ago

A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7

LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

$\frac{sigma}{\sqrt{n} }$