<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1
Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
Answer:
im sorry i dont know but this is for a challenge sorry
Step-by-step explanation:
Step-by-step explanation:
The exterior angles of an equilateral triangle will always have a measure of 120°.
Answer:
standard form : 2x + y = -2
