What is the question though
The equation represents height as a function of time.
The bullet was in the air for 75 seconds.
The equation is given as:

The time spent in the air is the time it takes the bullet to land on the ground.
When the bullet is on the ground, the height is:

So, we have:


Factor out t

Split
or 
represents when the shot is fired.
So, we solve for t in 
Collect like terms

Divide both sides by 16

Hence, the bullet was in the air for 75 seconds
Read more about height and time at:
brainly.com/question/2261757
I would say all you have to do is add those sides up then minus it with the total you’re trying to find
Answer:
a. True
b. True
c. False
d. False
Step-by-step explanation:
<u>First Table</u>
Length=10 feet, Width=4 feet
Area =10 X 4=40 Square Feet
<u>Second Table</u>
The second table is half as long as the first table.
Length =0.5 X 10 =5 feet
Area=5 X Width= 5w
The area of the second table is one fourth the area of the first table.
Area of Second Table =
X Area of first table
5w=
X 40
5w=10
Width of the Second table, w=2 feet
The following are true.
(a)The width of the second table is 2 feet.
(b) The area of the second table is 10 square feet.
Peggy has 12 practice sessions
The first step is finding the unit rate. We can do this by evaluating
21/1.75 divided by 1.75/1.75.
When you divide the two, you get 12.
To check your work you do 12(1.75) and you will get 21