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Kryger [21]
3 years ago
10

Are the two triangles congruent ? Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
8 0

Answer

YES

Step by step Explanation

MatroZZZ [7]3 years ago
4 0

Answer:

There is not information given to assume the triangles are congruent.

Step-by-step explanation:

You can tell if two triangles are congruent by any of the following rules:

Three sides are congruent (SSS),

Two angles and a side in between are congruent (ASA)

Two sides and an angle in between are congruent (SAS)

Two angles and a side connected to one of those angles are congruent (AAS)

Note: SSA (Two Sides & One Angle) does not work. I good way to remember is that it spells a bad word backwards :)

In this case, there are only two sides given, but there aren't any angles, so there is not enough information to conclude if they are congruent or not.

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Please solve I cannot solve this for the life of me
Paul [167]

Answer:

  • f(x) = x^5
  • g(x) = 2x -6 . . . . . and see below for other possible definitions

Step-by-step explanation:

You are given an expression for the composition H(x) = f(g(x)) and asked to decompose it into two functions. One way to do that is to look at what is being done to the variable in the function H(x):

  • the variable is multiplied by 2
  • 6 is subtracted from the product
  • the difference is raised to the 5th power.

One of the ways to create the functions g(x) and f(x) is to start at the top of this list and work your way down. Any subset of these transformations can be made into g(x). Then the rest of them are made into f(x).

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For example, using

  g(x) = 2x

Then the rest of the list is f(x):

  f(x) = (x-6)^5

so when you put 2x as the argument for f(x), you get ...

  H(x) = f(g(x)) = f(2x) = (2x -6)^5 . . . . . the function we want.

__

We could also do the first two steps of our list as g(x):

  g(x) = 2x -6

  f(x) = x^5

so

  H(x) = f(g(x)) = f(2x -6) = (2x -6)^5

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If we like, we can factor the expression for H(x):

  H(x) = (2(x -3))^5 = 32(x -3)^5

Using the methods above, we could write ...

  g(x) = x -3

  f(x) = 32x^5

so

  H(x) = f(g(x)) = f(x -3) = 32(x -3)^5

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The multiplication and the addition can be made into several parts. We could choose ...

  g(x) = (1/4)x -1

  f(x) = (8x +2)^5

so

  H(x) = f(g(x)) = f(1/4x -1) = (8(1/4x -1) +2)^5 = (2x -6)^5

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3 years ago
For what value of X,the point (x,x)lies on the line 2Y+3X-10=0
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Answer:

for x =2

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