$2\sqrt5+3\sqrt5-\sqrt5=(2+3-1)\sqrt5=4\sqrt5\\\\\text{Answer:}\ 4\sqrt5$
Look at the square root like "x", then
$2\sqrt5+3\sqrt5-\sqrt5=/2x+3x-x=4x/=4\sqrt5$

3 0

3 years ago

What is the answer to this question? Y=x^2-1 with the input as 5

mixas84 [53]

We can see that, when the input is 5, the output is 24.

<h3>How to evaluate an equation?</h3>

Here we have the equation:

$y = x^2 - 1$

Where y is the output and x is the input.

We want to evaluate it with the input as 5, so we need to replace the variable x by the number 5, we will get:

$y = 5^2 - 1 = 24$

Then we can see that, when the input is 5, the output is 24.

If you want to learn more about evaluating functions:

brainly.com/question/1719822

#SPJ1

4 0

2 years ago