2 angles that have the same angle measure are congruent.
Given that the two angles have the same angle measure.
Congruence is a term reserved for geometry. Two metrics are congruent when you can perfectly map to each other by mirroring, rotating, and translating without distortion.
We know that two shapes or objects are congruent if they have the same shape and the same size. For two angles to be congruent, they must coincide when they are overlapped. This is only possible if the two angles are equal.
Therefore, if two angles have the same measure, then they are said to be congruent.
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Answer:
13
Step-by-step explanation:
Given the equations f(x) = 2x - 3 and g(x) = 6 + 8/x.
We want to find f(g(4))
Essentially, what we are doing, is plugging in 4 into x for g(x) and the outcome of that is what we plug into x for f(x)
So first lets plug in 4 into x for g(x)
g(x) = 6 + 8/x.
We want to find g(4)
g(4) = 6 + 8/4
First divide 8 by 4
g(4) = 6 + 2
Then add 6 and 2
g(4) = 8
Now that we have found g(4) we want to plug the value of g(4), so 8 into f(x)
f(x) = 2x - 3
we want to find f(8)
f(8) = 2(8) - 3
* multiply 2 and 8 *
f(8) = 16 - 3
* subtract 3 from 16 *
f(8) = 13
and we are done!
So we can conclude that f(g(4)) = 13
A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point.
By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4.
<em>Answer: 4 units</em>
<u>Part a)</u>
Given the expression
Apply exponent rule: 
∵ 
Rewrite 81 as 3 · 27
Rewrite 54 as 2 · 27
Factor out the common term: 27m³n
Therefore,
<u>Part B)</u>
Given the expression
Apply exponent rule:
Rewrite as
Factor out common term 5y²x²z
Therefore,
I believe it is A
Hope this answer helps
