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3 years ago

4x/5-5/2x^8 এর বিস্তৃতিতে শেষের তৃতীয় পদ নির্ণয়

Mathematics

1 answer:

insens350 [35]3 years ago

5 0

Answer:

Fr dude-

Step-by-step explanation:

What does that even say Imaaoo

Welp if you wanted me to write that in standard form then here ya go:

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ohan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. which explains whether his solut

klio [65]

-2 | 8-x| - 6 = -12...add 6 to both sides
-2 |8-x| = -12 + 6
-2 |8-x| = - 6...divide both sides by -2
|8-x| = -6/-2
|8-x| = 3

8 - x = -3 -(8 - x) = -3
-x = -3-8 -8 + x = -3
-x = -11 x = -3 + 8
x = 11 x = 5

not correct.....sign error

5 0

3 years ago

What is equivalent to<br> -9(x - 4 ) - 6x

Lapatulllka [165]

The answer would be -15x+36. To solve this equation, you would first use distributive property and distribute the -9 to the values inside the parentheses (or multiply them). So, you would multiply -9 and x and -9 and -4 to get -9x+36-6x. Then, you combine like terms, which are -9x and -6x to get -15x. You can't simplify any further without knowing the value of x. Hope this helps!

4 0

3 years ago

Which numbers are greater than 0.7? 0.37, 0.9, 0.08, 0.69, 0.71

nikitadnepr [17]

Hello!

The following numbers are greater than 0.7:

0.9 and 0.71.

5 0

2 years ago

In another problem in my homework, it says look at problem 4, problem 4 has to do with the question about seans team when it had

notka56 [123]

I dont know because I’m confused

3 0

3 years ago

Which of the following can be used to calculate the volume of water inside the fish bowl?

Lunna [17]

The volume of a sphere can be calculated as

$V=\frac{4}{3}\pi r^3$

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

$V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3$

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

$r=\frac{AB}{2}=\frac{12}{2}=6$

Let's put it into our equation

$\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\ \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}$

The problem says to use

$\pi\approx\frac{22}{7}$

Then

$V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

$V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

8 0

1 year ago

4x/5-5/2x^8 এর বিস্তৃতিতে শেষের তৃতীয় পদ নির্ণয়​

4x/5-5/2x^8 এর বিস্তৃতিতে শেষের তৃতীয় পদ নির্ণয়