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aivan3 [116]
3 years ago
10

4x/5-5/2x^8 এর বিস্তৃতিতে শেষের তৃতীয় পদ নির্ণয়​

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

Fr dude-

Step-by-step explanation:

What does that even say Imaaoo

Welp if you wanted me to write that in standard form then here ya go:

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C=2m+d solve for m plz
Pavel [41]
Isolate the m, go backwards for PEMDAS.

C = 2m + d
C (-d) = 2m + d (-d)
C - d = 2m
(C - d)/2 = 2m/2
m = (C - d)/2

m = (C - d)/2 is your answer

hope this helps
 
7 0
3 years ago
Can't put it in look at photo pls​
Katyanochek1 [597]

x ^{ - n}  + x ^{2n}

That's my answer Brainliest me!

6 0
2 years ago
Please answer In(5x-3)=4
Goshia [24]

Answer:

\huge\boxed{Answer\hookleftarrow}

(5x - 3) = 4 \\ 5x - 3 = 4 \\ 5x = 4 + 3 \\ 5x = 7 \\ x =  \frac{7}{5}  \\ x = 1.4

<h3>⎆ The answer will be, <u>x = 7/5 (in fraction form) & x = 1.4 (in standard form)</u><u>.</u></h3>

# ꧁❣ RainbowSalt2²2² ࿐

8 0
2 years ago
Suppose $886.20 is listed for $5 less. A third catalog has $886.20 marked down 20% ,which is the better deal?
Ipatiy [6.2K]

Answer:

20% of $886.20 is 177.24 so the better deal would be 20% off

Step-by-step explanation:

4 0
2 years ago
On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th
Schach [20]

Answer:

Average speed   is 37.35 mi/h

Step-by-step explanation:

given data

leave =  34 minutes before

church distance =  12.0 miles

average speed first 17 minutes =  5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × \frac{17}{60}

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed  = \frac{distance}{time}

Average speed  = \frac{10.584}{\frac{17}{60}}

Average speed   is 37.35 mi/h

3 0
3 years ago
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