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romanna [79]
2 years ago
7

What is the value of c so that -12 and 12 are both solutions of x^2-c=108? ​

Mathematics
1 answer:
murzikaleks [220]2 years ago
8 0

Answer:

c=36

Step-by-step explanation:

  1. Because x^2-c=108 can be rewritten as x^2-c-108=0, finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that (+-)12^2-c-108=0.
  2. Because 12^2=(-12)^2=144, we must find c so that 144-c-108=0.
  3. Because 144-108=36, c=36.
  4. To check, replace c=36 in the initial equation, and check  it is a solution for x=(+-)12.
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