Solving systems of linear inequalities
1 answer:
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Answer:
34 games
Step-by-step explanation:
let the number of losses be
let the number of victories be
<u>the Phoenix murmur had 12 more victories than losses:</u>
<u>The number of victories they had was one more than two times the number of losses:</u>
<em>We have 2 expressions for , equating these 2, we can solve for
:</em>
So 11 games, they lost.
Using this value, we can plug into the 1st equation to solve for v:
So 23 games, they won.
Given that no draws, they played a total of 23 + 11 = 34 games this season
Answer:
Step-by-step explanation:
x is the number of years. y is the population after x years.
Each year, the population decreases by 22%, since 100% - 22% = 78%, and 78% = 0.78, each year, the population is 0.78 of the previous year's population.
year zero: y = 300
year 1: y = 300 * 0.78 = 300 * (0.78)^1
year 2: y = (300 * 0.78) * 0.78 = 300 * (0.78)^2
year 3: y = ((300 * 0.78) * 0.78) * 0.78 = 300 * (0.78)^3
year x: y = 300(0.78)^x