Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Replace x with y and solve for y~
y=2*
x=2^y
log x = y log 2
y=log x / log 2
Hope this helps and leave a brainliest to help me reach expert ;)
Answer:
x = 21°
Step-by-step explanation:
Vertical angles have the same measures, therefore:
3x - 30 = 2x - 9
x - 30 = -9
x = 21°
Answer:
α = 3.5 rad
Step-by-step explanation:
α = 2*Area/r^2
α = 2*16 in^2/(3in)^2
α = 3.5555 radians