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Serhud [2]
3 years ago
7

Tan2 theta - sin2 theta= sin2 theta × tan2 theta​

Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Hi there!

We can begin by solving the left side:

tan²Θ - sin²Θ =

Rewrite tan:

\frac{sin^2\theta}{cos^2\theta} - sin^2\theta =

Multiply sin²Θ by cos²Θ to get a common denominator:

\frac{sin^2\theta}{cos^2\theta} - \frac{sin^2\theta * cos^2\theta}{cos^2\theta}=

Subtract:

\frac{sin^2\theta- sin^2\theta * cos^2\theta}{cos^2\theta} =

Factor out sin²Ф from the numerator:

\frac{sin^2\theta(1 - cos^2\theta)}{cos^2\theta} =

Rewrite 1 - cos²Ф as sin²Ф (Pythagorean identity)

\frac{sin^2\theta(sin^2\theta)}{cos^2\theta} =

Simplify:

\frac{sin^4\theta}{cos^2\theta} =

Split into sin and tan:

sin^2\theta * \frac{sin^2\theta}{cos^2\theta} =

Rewrite:

sin^2\theta * tan^2\theta

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