Pls help !!!!!!!!!!!!!!!!!

Help plz find the equation

tatiyna

Question # 1

Step-by-step Explanation:

Given

$\frac{1}{2}\div \frac{2}{3}$

solving

$\frac{1}{2}\div \frac{2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{1}{2}\times \frac{3}{2}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{1\times \:3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3$

$=\frac{3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4$

$=\frac{3}{4}$

Therefore, completing the blanks:

$\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}$

Question # 3

Step-by-step Explanation:

Given

$\frac{2}{5}\div \frac{3}{4}$

solving

$\frac{2}{5}\div \frac{3}{4}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2}{5}\times \frac{4}{3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2\times \:4}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8$

$=\frac{8}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15$

$=\frac{8}{15}$

Therefore, completing the blanks:

$\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}$

Question # 5

Step-by-step Explanation:

Given

$\frac{3}{4}\div \frac{5}{7}$

solving

$\frac{3}{4}\div \frac{5}{7}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{3}{4}\times \frac{7}{5}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{3\times \:7}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21$

$=\frac{21}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20$

$=\frac{21}{20}$

Therefore, completing the blanks:

$\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}$

6 0

3 years ago

What are the solutions to x2 - 6x - 7 = 0?

Olin [163]

Answer:

x=7 x=-1

Step-by-step explanation:

x^2 - 6x - 7 = 0

Factor

What two numbers multiply to -7 and add to -6

-7*1 =-7

-7+1 = -6

(x-7) (x+1) = 0

Using the zero product property

x-7 =0 x+1 =0

x=7 x=-1

8 0

3 years ago

Read 2 more answers

Andrew pays $1824 per year in tuition. How much should he budget monthly for it ?

Lina20 [59]

I would so go with B I'm not sure if that's the correct answer though but that's what I would go with

4 0

3 years ago

Read 2 more answers

Five sixths divided by three

chubhunter [2.5K]

Answer:

3 and 3/5

Step-by-step explanation:

5/6 divided by 3/1 is the same as 6/5 times 3/1 so,

18/5=3and3/5 as the answer

8 0

3 years ago

Read 2 more answers

What is the monthly finance charge if the average daily balance is $15, the daily periodic rate is 0.06%, and the number of days

MariettaO [177]

Given

The average daily balance is $15

The daily periodic rate = 0.06%

The number of days in the cycle is 30

Find out the monthly finance charge.

To proof

Let us assume that the monthly finance charge = x

As given in the question

The average daily balance = $15

daily periodic rate = 0.06%,

First convert 0.06% in decimal form

$=\frac{0.06}{100}$

= 0.0006

Daily finance charge = 0.0006 × 15

= 0.009

number of days in the cycle is 30

now

monthly finance charge

Than the equation becomes

x = 15 × 0.0006 × 30

x = 0.009× 30

x = $0.27

Thus the monthly finance charge is $0.27

Hence proved

4 0

4 years ago