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ZanzabumX [31]
3 years ago
6

If g(x) = 3^Vx-123, find g( - 2).

Mathematics
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

g(-2) = -5

Step-by-step explanation:

We are given the following function:

g(x) = \sqrt[3]{x - 123}

Find g( - 2).

This means that we find g when x = -2. So

g(-2) = \sqrt[3]{-2 - 123} = \sqrt[3]{-125} = \sqrt[3]{-5^3} = -5

So

g(-2) = -5

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3c-2(c+10)=7c-5(c+2)
jeka94

Answer: C= -10

Step-by-step explanation: First step: simplify both sides of the equation

3c−2(c+10)=7c−5(c+2)

3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)

3c+−2c+−20=7c+−5c+−10

(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)

c + -20 = 2c - 10

c - 20 = 2c - 10

Step 2: Subtract 2c from both sides

c - 20 - 2c = 2c -10 - 2c

−c−20=−10

Step 3: Add 20 to both sides

−c−20+20=−10+20

−c=10

Step 4: Divide both sides by -1

-c/-1 = 10/-1

C=-10

   

6 0
3 years ago
A number b increased by 3 is greater than or equal to -26
photoshop1234 [79]

A number b increased by 3 is greater than or equal to -26:

b+3\geq-26\qquad\text{subtract 3 from both sides}\\\\\boxed{b\geq-29}

5 0
3 years ago
Reposting becuase it want let me edit my last one and somebody spam answered it.
harkovskaia [24]

Answer:

5

5Step-by-step explanation:

If you use the distance formula you can solve it pretty easily. The distance formula is:

d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \\

The two points you want are A and D. A is (-1, -4) and D is (3, -1). Plug that into the formula...

d = \sqrt{(3 - (-1))^2 + (-1 - (-4))^2}

d = \sqrt{4^2 + 3^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

5

I can solve it in a different way if you want me to.

8 0
3 years ago
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