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Ugo [173]
3 years ago
7

Can someone please help and explain? thank you. will give brainliest

Mathematics
1 answer:
Alik [6]3 years ago
3 0

Answer:

Domain: -4 ≤ x ≤ 4

General Formulas and Concepts:

<u>Algebra</u>

  • Domain is the set of x-values that can be inputted into function f(x)

Step-by-step explanation:

According to the graph, we see that our x-values span from -4 to 4. Since both are closed dots, they are inclusive in the domain:

[-4, -4] or -4 ≤ x ≤ 4

You might be interested in
Consider three consecutive positive integers, such that the sum of the
Greeley [361]

Answer:

  17

Step-by-step explanation:

Let x represent the smaller integer. Then we have ...

  (x +1)² +(x +2)² = 40x +5

  2x² +6x +5 = 40x +5

  x² -17x = 0 . . . . . subtract (40x+5), divide by 2

  x(x -17) = 0 . . . . . factor

The solution of interest is x = 17.

The smaller integer is 17.

4 0
3 years ago
Find the measure of x.
Ratling [72]
<h3>Answer:  B.  x = 6</h3>

==========================================================

Explanation:

Since the vertical lines are parallel, this means the alternate exterior angles shown are congruent.

Set them equal to each other and solve for x.

15(x+2) = 120

15x+30 = 120

15x = 120-30

15x = 90

x = 90/15

x = 6

Or we could have the steps like this

15(x+2) = 120

x+2 = 120/15

x+2 = 8

x = 8-2

x = 6

7 0
2 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
3 years ago
How do I solve these questions? <br> 5(1+9v)<br> 20b+12<br> -9/4r=-9/2
MatroZZZ [7]
5(1+9v) = 5+ 45v
20b+12= 4(5b+3)
And the last one is r=2
Hope this helps!
7 0
3 years ago
Y=-x^2+20x-64 what is the max height
Inessa [10]

Answer:

36

Step-by-step explanation:

The maximum height is the y-coordinate of the vertex

given a quadratic in standard form : ax² + bx + c : a ≠ 0

then the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - x² + 20x - 64 is in standard form

with a = - 1, b = 20 and c = - 64, hence

x_{vertex} = - \frac{20}{-2} = 10

substitute x = 10 into the equation for y

y = - (10)² + 20(10) - 64 = 36 ← max height


8 0
4 years ago
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