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Bess [88]
3 years ago
5

Can someone Help me please

Mathematics
1 answer:
leonid [27]3 years ago
5 0

Step-by-step explanation:

<h2><em><u>Given</u></em><em><u>,</u></em></h2>

<em><u>In</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>ABC</u></em><em><u>.</u></em> <em><u>In</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>DBC</u></em>

AB. = DB.

<em>[</em><em>Given</em><em>]</em>

<ABC. = <DBC

<em>[</em><em>Given</em><em>]</em>

BC. = BC

<em>[</em><em>Common</em><em> </em><em>side</em><em>]</em>

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>As</u></em><em><u> </u></em><em><u>two</u></em><em><u> </u></em><em><u>sides</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>angle</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>ABC</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em><em><u>DBC</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>equal</u></em><em><u>. </u></em>

<h2><em><u>Therefore</u></em><em><u>, </u></em></h2>

<em><u>Triangle</u></em><em><u> </u></em><em><u>ABC</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>congruent</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>Triangle</u></em><em><u> </u></em><em><u>DBC</u></em>

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Answer:

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Step-by-step explanation:

1. Factor the 2 out of the equation (don't forget about it - it will be used later). This gives you x^2 + 6x + 7

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5. Subtract the 2 over. This gives you (x + 3)^2 - 2

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