2. You are rolling a number cube. What is the probability that you will roll a
1 answer:
You might be interested in
A) I included a graph, look below.
B)
Input the y in x = y + 3.
x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0
Input that x value in y = -4x - 3
y = -4(0) - 3
y = 0 - 3
y = -3
(0, -3)
C)
Convert both equations to Standard Form.
x = y + 3
Subtract y from both sides.
x - y = 3
y = -4x - 3
Add 4x to both sides.
4x + y = -3
Add the equations together.
4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0
Input that into one of the original equations.
0 = y + 3
Subtract 3 from both sides.
-3 = y
(0, -3)
B)
Input the y in x = y + 3.
x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0
Input that x value in y = -4x - 3
y = -4(0) - 3
y = 0 - 3
y = -3
(0, -3)
C)
Convert both equations to Standard Form.
x = y + 3
Subtract y from both sides.
x - y = 3
y = -4x - 3
Add 4x to both sides.
4x + y = -3
Add the equations together.
4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0
Input that into one of the original equations.
0 = y + 3
Subtract 3 from both sides.
-3 = y
(0, -3)
Answer:
- p=0.7103 (4-game series)
- p=0.6480 (2-game series)
Step-by-step explanation:
Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:
#We find probabilities for the different values of i:
Hence, probability of the stronger team winning overall is:
#Define Y as the random variable for winning 2/3 games.:
Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480
The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)
Answer:
IT is not
Step-by-step explanation:
Let's replace. If it's a solution, it means that BOTH equations has to be true.
Now, the second equations seems good - indeed.
First alas isn't. RHS is 142, which is totally not the same as -10.