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MissTica
3 years ago
13

Exhibit 9-2 The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the cu

stomers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minute. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes. Refer to Exhibit 9-2. At a .05 level of significance, it can be concluded that the mean of the population is _____.
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

At a .05 level of significance, it can be concluded that the mean of the population is significantly more than 3 minutes.

Step-by-step explanation:

We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes.

At the null hypothesis, we test if the mean is of at most 3 minutes, that is:

H_0: \mu \leq 3

At the alternative hypothesis, we test if the mean is of more than 3 minutes, that is:

H_1: \mu > 3

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

3 is tested at the null hypothesis:

This means that \mu = 3

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minute.

This means that n = 100, X = 3.1, \sigma = 0.5

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{3.1 - 3}{\frac{0.5}{\sqrt{100}}}

z = 2

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 3.1, which is 1 subtracted by the p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228

The p-value of the test is of 0.0228 < 0.05, meaning that the is significant evidence to conclude that the mean of the population is significantly more than 3 minutes.

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2 years ago
Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0
fomenos

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

x=\frac{1+2i}{5}\text{     or    }\frac{1-2i}{5}

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}

Note that:

√-1 = i

x=\frac{2\pm\sqrt[]{16\times-1}}{10}

x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}x=\frac{2\pm4i}{10}x=\frac{2}{10}\pm\frac{4i}{10}x=\frac{1}{5}\pm\frac{2}{5}ix=\frac{1\pm2i}{5}

That is;

\text{Either x=}\frac{1+2i}{5}\text{ or     x=}\frac{1-2i}{5}

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11 months ago
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Answer:

12.5%

Step-by-step explanation:

The price increased from 800 to 900. So what is the PERCENTAGE INCREASE??

The increase is 900 - 800 = 100

To find this in terms of original, we need to divide 100 by 800 and multiply by 100 to get the "percentage". Let's do it:

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alina1380 [7]

Answer:

The answer (D)

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