Step-by-step explanation:
every triangle inscribed into a circle with the baseline being a diameter of the circle must be a right-angled triangle.
therefore,
angle XVY = 90°.
for VY we can use Pythagoras
c² = a² + b²
with c being the Hypotenuse (the line opposite of the 90° angle, in our case XY).
XY = 2×ZY = 2×17 = 34.
so,
34² = 30² + VY²
VY² = 34² - 30² = 1156 - 900 = 256
VY = 16
We know that m<JKL = m<JKM + m<MKL
Let's substitute the values from the picture into our equation above.
10x - 11 = 43 + 8x - 20
Combine like terms.
10x - 11 = 8x + 23
Subtract 8x from both sides and add 11 to both sides.
2x = 34
Divide both sides by 2
x = 17
m<MKL = 8x - 20 = 8(17) - 20 = 136 - 20 = 116 degrees.
m<JKL = 10x - 11 = 10(17) - 11 = 170 - 11 = 159 degrees.
A) x=4
B) x= -3
C) x= -1/6
D) x=24
<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
To me it sounds like 4 divided by n +5
