All categories

2 years ago

Can anyone help me with these problems? but I need details of how to do it, please!

Mathematics

1 answer:

Agata [3.3K]2 years ago

8 0

This one is really challenging for US

You might be interested in

Hi so this question is super confusing! I can't even figure it out

frutty [35]

Answer:

i think it's n/2 may be even and 3n+1 is odd. They succumb to 3n if that helps.

Step-by-step explanation:

hope it helps, have a good day/night

6 0

2 years ago

I NEED HELP PLEASE HURRY, THANKS! :)

Dvinal [7]

Answer:

using SOHCAHTOA

COS THETA WILL BE EQUALS TO ROOT 5/3 AND TAN THETA WILL BE EQUALS TO 2ROOT 5/3

8 0

3 years ago

Read 2 more answers

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

The storage container below is in the shape of a rectangular prism with a height of 6 feet and a length that is 2 feet more than

yaroslaw [1]

The answer is B.) V = 6w2 + 12w

8 0

3 years ago

Find the x-intercept of the line 3x - 9y = 15.

erastovalidia [21]

Answer:

The x-intercept is 5.

Some people prefer you right it as a point (5,0).

Step-by-step explanation:

The x-intercept can be found by setting y=0 and solving for x.

Just like to find the y-intercept you can set x=0 and solve for y.

Let's find the x-intercept.

So we will set y=0 and solve for x:

3x-9y=15

3x-9(0)=15

3x-0 =15

3x =15

Divide both sides by 3:

x =15/3

x =5

So the x-intercept is (5,0).

4 0

3 years ago