PLS HELP ME I ADDED SCREENSHOT

Mathematics

2 answers:

aniked [119]3 years ago

5 0

Answer:

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Step-by-step explanation:

Cerrena [4.2K]3 years ago

4 0

I don't see a screenshot

Did you post it separately??

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Find an equation of the tangent line to the graph of

Allisa [31]

Answer:

$y- y_o = m(x-x_o)$

For this case m represent the slope and is given by $m= g'(4) = 2$ and from the other condition given we know that $x_o = 4, y_o =-3$ . And replacing we got:

$y -(-3) = 2 (x-4)$

And if we reorganize the terms we have:

$y+3 = 2x -8$

And subtracting 3 in both sides we got:

$y = 2x -11$

Step-by-step explanation:

For this case we have the following function y=g(x) and we want to find the tangent line to this function using the conditions: $g(4) =-3, g'(4)=2$

So we need a function like this one:

$y- y_o = m(x-x_o)$

For this case m represent the slope and is given by $m= g'(4) = 2$ and from the other condition given we know that $x_o = 4, y_o =-3$ . And replacing we got:

$y -(-3)=2(x-4)$