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3 years ago

-16-4 = ? 4.? = 4. So, -16-4=

Mathematics

2 answers:

Nutka1998 [239]3 years ago

6 0

Answer:

-16-4=20

can try photo math

App

just gotta take a picture of your questions and your

answers will pop up :)

PIT_PIT [208]3 years ago

4 0

Answer:

It's -16-4

Step-by-step explanation:

Therefore its negative mins a neg so its like a debt mins a debt so it remains a debt.

Therefore its- 20

Plzzz brainlest

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(3c to the 5th power d 1/2)3

Alik [6]

To simplify the expression it would be $\frac{27c15d3}{8}$

5 0

3 years ago

Solve log6x+ log14=1

LekaFEV [45]

Answer:

x = 5/42 or 0.119

Step-by-step explanation:

log(6x) + log(14) = 1

log(6x × 14) = 1

log(84x) =

84x = 10¹

84x = 10

x = 10/84

x = 5/42 or 0.119

8 0

3 years ago

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taurus [48]

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4 0

3 years ago

Read 2 more answers

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago

An object dropped from a height of 600 feet has a height, h(t), in feet after t seconds have elapsed, such that h(t)=600 - 16t^2

gulaghasi [49]

Answer:

t as a function of height h is t = √600 - h/16

The time to reach a height of 50 feet is 5.86 minutes

Step-by-step explanation:

Function for height is h(t) = 600 - 16t²

where t = time lapsed in seconds after an object is dropped from height of 600 feet

t as a function of height h

replacing the function with variable h

h = 600 - 16t²

Solving for t

Subtracting 600 from both side

h - 600 = -16t²

Divide through by -16

600 - h/ 16 = t²

Take square root of both sides

√600 - h/16 = t

Therefore, t = √600 - h/16

Time to reach height 50 feet

t = √600 - h/16

substituting h = 50 in the equation

t = √600 - 50/16

t = √550/16

t= 34.375

t = 5.86 minutes

7 0

3 years ago