This is my question it is in the screen shot please help me.

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

4 in = 10.2 cm
7kg = 15.4 lbs
6 gal = 22.7 L
66 ft = 19.8 m

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PLEASE ANSWER ASAP *picture attached*<br>f(x) = x2 + 1 g(x) = 5 – x

Eva8 [605]

Answer:

$x^{2} +x-4$

Step-by-step explanation:

To get the answer just subtract f(x) by g(x)

The work is shown below:

$(f-g)(x)= f(x)-g(x)\\\\(f-g)(x)= (x^{2} +1)-(5-x)\\\\(f-g)(x)= x^{2} +1-5+x\\\\(f-g)(x)= x^{2} -4+x\\\\(f-g)(x)= x^{2} +x-4\\\\$

7 0

3 years ago

Simplyify t^12/t^6 *PLEASE HELP*

Julli [10]

Answer:

Step-by-step explanation:

In division when bases are same you do top exponent minus bottom exponent.

So here you do t^(12-6) which is t^6.

3 0

3 years ago

Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In addition, there is

Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so $P(A) = 0.13$ .

In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. $P(B/A)$ is the probability that the person is a male, given that he/she jogs. So $P(B/A) = 0.156$

The Bayes theorem states that:

$P(B/A) = \frac{P(A \cap B)}{P(A)}$

In which $P(A \cap B)$ is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.