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3 years ago

A four foot tall girl cast a shadow of 6 feet. A shade tree cast a shadow of 24feet. What is the height of the tree?

1 answer:

5 0

The answer is 16.
the girls shadow is 6 feet, and the trees is 24. you get to 24 by multiplying by 4. so do the same thing for the height. if the girls height is 4, multiply by 4 to get to the trees height. 4x4 is 16.

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I need help pleasee

AlexFokin [52]

Answer:

2x+3=-13

x=5

Step-by-step explanation:

it says 2 times a number which would be the 2x, and it says the sum of that and 3 which would be 2x+3 and it says is 13. 2x+3=13

now solving it

2x+3=13

subtract 3 from both sides

2x=10

and divide 2 from both sides

x=5

5 0

3 years ago

Read 2 more answers

The equation P=4s represents the perimeter P of a square with side length s. What is the perimeter of a square with a side lengt

PilotLPTM [1.2K]

Answer:

20 feet

Step-by-step explanation:

s= side

P= 4s

I our case, s is 4, so 4*5 is 20.

Hence,

P=20

Hope this helps!

6 0

2 years ago

Answer:

emmainna [20.7K]

Let the numbers be n, n+2, n+4

Sum equals too= 13+2(n+4), which is 2n+21

a) Equation--> n+n+2+n+4= 2n+21

b) Solution--> 3n+6= 2n+21

=> n= 15

c) Second number--> 17 (15+2)

Third number--> 19 (15+4)

d) 15+15+2+15+4=30+21

=> 51= 51

So, the equation is true.

And pls mark me brainliesttt :)))

8 0

2 years ago

A 4-cup carton of frozen yogurt costs $3.64. What is the price per pint?

Musya8 [376]

Answer:

$0.91.

91 cents.

Step-by-step explanation:

have a good day!

7 0

3 years ago

A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0

3 years ago