PLEASE it’s due tonight help me! All help will be greatly appreciated.
1 answer:
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Given
We have to set the restraint
because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:
The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have
So, we have to impose
Squaring both sides, we have
The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.
<u>Given</u>:
Given that the bases of the trapezoid are 21 and 27.
The midsegment of the trapezoid is 5x - 1.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the trapezoid midsegment theorem.
Applying the theorem, we have;
where b₁ and b₂ are the bases of the trapezoid.
Substituting Midsegment = 5x - 1, b₁ = 21 and b₂ = 27, we get;
Multiplying both sides of the equation by 2, we have;
Simplifying, we have;
Adding both sides of the equation by 2, we get;
Dividing both sides of the equation by 10, we have;
Thus, the value of x is 5.