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garik1379 [7]
3 years ago
10

Look at photo because I don’t get it

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

a) (-2,2), (-1,-1), (1,-1), (3,7)

b) x=1.4

Lelechka [254]3 years ago
7 0

Answer:

a) (-2, 2), (-1, -1), (1, -1), (3, 7)

b) x = 1.4

Step-by-step explanation:

a) Plug in your x & solve for y.

y = (-2)^2 - 2\\y = 2\\y = (-1)^2 - 2\\y = -1\\y = (1)^2 - 2\\y = -1\\y = (3)^2 -2\\y = 7

b) Same thing as a, but just plug in 0 for y & solve for x

0 = x^2 -2\\2 = x^2\\\sqrt(2) = x\\1.4 = x

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Box A contained 1.67 kg of flour. Box B contained 8600 g of flour. After same amount of
rjkz [21]

Answer:

The amount of flour added to each box was 0.64 kg

Step-by-step explanation:

Let

x ----> the amount of flour added to each box in kg

Remember that

1 kg=1,000 g

8,600 g=8,600/1,000=8.6 kg

we know that

The linear equation that represent this situation is

(8.6+x)=4(1.67+x)

Solve for x

8.6+x=6.68+4x

4x-x=8.6-6.68

3x=1.92

x=0.64 kg

3 0
3 years ago
Change 4 5/7 and 7 into improper fractions
Elden [556K]
ANSWER:



4 5/7= 83/7



7= 7/1
4 0
3 years ago
(2x2 – 18)(x+3)(2 – 3) = 2x4 – 36x2 + 162
lubasha [3.4K]

Answer:

X=4

Step-by-step explanation:

I'm took lazy to explain it step by step sorry, but I'm positive that's the correct answer.

6 0
2 years ago
Read 2 more answers
Pine bluff middle school is having its annual spring fling dance which will cost $475 the student treasure reported that the dan
Cloud [144]
4t + 75 => 475, t = 100

Is this what you were looking for?
5 0
3 years ago
A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}
&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\
&------&------&------\\
\textit{pure water}&x&0.00&0x\\
\textit{6\% solution}&5&0.06&0.3\\
-----&------&------&------\\
mixture&y&0.04&0.04y
\end{array}
\\\\\\
\begin{cases}
x+5=\boxed{y}\\
0x+0.3=0.04y\\
---------\\
0.3=0.04\left( \boxed{x+5} \right)
\end{cases}
\\\\\\
0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
3 0
3 years ago
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