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3 years ago

Help needed again ASAP!

Mathematics

1 answer:

Ksju [112]3 years ago

7 0

Answer:

12: 26

13: ,10 player

14: 15.

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Write a rule for the following functions. I need help fast!

marishachu [46]

Answer:

20. y = 3·3^x

21. y = (1/3)^x

Step-by-step explanation:

These exponential functions can be written in the form ...

y = a·b^x

where a is the value of y when x=0, and b is the common ratio between terms that have x different by 1.

20. The ratio is 9/3 = 3; the multiplier is 3 (the value of y when x=0), so the function is ...

y = 3·3^x

21. The ratio is (1/3)/1 = 1/3; the multiplier is 1, so the function is ...

y = (1/3)^x

_____

<em>Alternate solution</em>

Each of these can be written in a more compact form:

20: y = 3^(x+1)

21: y = 3^(-x)

5 0

3 years ago

Can You Please help Me

faust18 [17]

Answer:

Hope this helps you! Have a great day. :)

3 0

3 years ago

Felipe bought 3/4 of a pound of American cheese at the deli. She used 1/2 of the cheese to make sandwiches. How much cheese did

seraphim [82]

She used 3/8 of the cheese. Since she used 1/2 <em>of</em> 3/4, you multiply 3/4 times 1/2. If you multiply straight across, the answer should be 3/8. If you need further explanation, just ask! Hope this helps! =D :D

6 0

3 years ago

Read 2 more answers

Quiz: Areas and Volumes of Similar Solids

Otrada [13]

Answer:

I think 320

Step-by-step explanation:

sorry if wrong but I think it 320

6 0

2 years ago

A three-digit number has tens digit two greater than the units digit and the hundreds digit one greater than the tens digit. The

Paha777 [63]

Answer:

875

Step-by-step explanation:

As given, there is a three digit number

So, let assume three digit number be `xyz`.

Now, as given tens digit is 2 greater than the unit digit.

∴ $y= 2+z$

Next, the hundred digit one greater than the tens digit.

∴ $x= 1+y$

The sum of the tens and the hundreds digits is three times the units digit.

∴ $x+y= 3z$

Now, substituting the value in the equation.

$x+y= 3z$

⇒ $(1+y)+y= 3\times (y-2)$

solving it to get value of y

⇒ $2y+1= 3y-6$

⇒ $-y= -7$

∴ $y=7$

Next, finding value of z

y= $2+z$

substituting the value of y and subtracting both side by 2

∴ z= $7-2= 5$

Last, finding the value of x

$x=1+y$

substituting the value of y

∴ x= 8

xyz= 875

5 0

3 years ago