A bicycle wheel has a circumference of 75 inches. What is the approximate radius of the wheel?

PLEASE HELPPPP(BRAINLIEST FOR RIGHT ANSWER)

Thepotemich [5.8K]

Answer:

The relation between polar and Cartesian coordinates are

r2=x2+y2

tan

θ

=

y

x

,

x

=

r

cos

θ

,

y

=

r

sin

θ

r

=

8

sin

θ

∴

r

⋅

r

=

r

⋅

8

sin

θ

or

r

2

=

8

r

sin

θ

∴

x

2

+

y

2

=

8

y

or

x

2

+

y

2

−

8

y

=

0

or

x

2

+

y

2

−

8

y

+

16

=

16

or

x

2

+

(

y

−

4

)

2

=

4

2

Rectangular form is

x2+(y-4)2=42

graph{x^2+(y-4)^2=16 [-20, 20, -10, 10

Step-by-step explanation:

i created it that way so yall will take a longer time to answer

8 0

3 years ago

Read 2 more answers

List the next four multiples of fraction 7/12

Sidana [21]

<h2>Hello!</h2>

The answer is:

$\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5$

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of $\frac{7}{12}$ are:

$\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}$

Have a nice day!

6 0

3 years ago

sandy has $200 in her bank account. if she writes 6 checks for exactly $19.98, what expression describes the change in her bank

kkurt [141]

6x+19.98=200
200-19.98=6x
X= 200-19.98/6
= solve for it.

7 0

3 years ago

Read 2 more answers

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$