Given m||n, find the value of x.<br><br> 168<br><br><br> PLEASE HELP

The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample

soldier1979 [14.2K]

The 99% confidence interval for the true mean is given by:

$\bar{x}\pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

where:

$\bar{x}$ is the sample mean = 69.7
$\sigma$ is the standard deviation = 2.8
$z_{\alpha/2}$ is the test statistics = 2.58 for for 99% confidentce interval.
n is the sample size = 772.

Therefore, the 99% confidence interval is:

$69.7\pm2.58\left( \frac{2.8}{\sqrt{772}} \right)=69.7\pm2.58(0.1008) \\ \\ =69.7-0.26\leq\mu\leq69.7+0.26 \\ \\ =69.44\leq\mu\leq69.96$

6 0

3 years ago

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I need to know how to do this, plz explain-Which function grows at the fastest rate for increasing values of x?

saul85 [17]

If the first function is
.. h(x) = 2^x
it will be the one that grows the fastest. The exponential function with the largest base value will grow faster than any polynomial.

7 0

3 years ago

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Sales of a new line of athletic footwear are crucial to the success of a newly formed company, Fleet Shoes. Fleet wishes to esti

Murrr4er [49]

Answer:

The number of weeks required = 216 weeks

Step-by-step explanation:

Given that:

Margin of Error E = 200

Confidence interval = 95% = 0.95

Level of SIgnificance = 1 - C.I

= 1 - 0.95

= 0.05

Standard deviation = 1500

The Critical value for Z :

$Z_{\alpha/2} =Z_{0.05/2} \\ \\ = Z_{0.025} = 1.96$

The number of weeks( i.e the sample size (n) ) required is :

$n = (\dfrac{Z_{\alpha/2} \times \sigma}{E})^2$

$n = (\dfrac{1.96 \times 1500}{200})^2$

$n = (14.7)^2$

n = 216.09

n ≅ 216 weeks

8 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

zheka24 [161]

<h2>Hello!</h2>

The answer is:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$