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3 years ago

Please help me with this. (easy)

Mathematics

1 answer:

azamat3 years ago

7 0

Answer:

8. 2/7 9. 3/4 10. 3/5

Step-by-step explanation:

simplify 4/14 by 2, simplify 15/20 by 5, and simplify 21/35 by 7, hope this helps

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Need this answer for this

Alexandra [31]

Answer:

the point (0,6) is the point that is 1/6 of the way

5 0

2 years ago

Your turn!<br> Problem 1<br> Determine the translation that maps point B(2, 1) to point B'(-4,5).

Charra [1.4K]

Answer:

Shift 4 units up, and 4 units to the left.

Step-by-step explanation:

4 0

3 years ago

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

Find the volume of a pyramid with a square base, where the side length of the base is

irina [24]

The volume of the pyramid is 167.6 cube inch (approx).

Step-by-step explanation:

Given,

Each length (l) of the base of the pyramid = 8.3 in

Height(h) of the pyramid = 7.3 in

To find the volume of the pyramid.

Formula

Volume of the pyramid = $\frac{1}{3}$ ×area of the base×height

Area of the base = l²

Now,

The volume of the pyramid = $\frac{1}{3}$ ×l²×h

= $\frac{1}{3}$ ×8.3²×7.3 cube inch = 167.6 cube inch (approx)

8 0

4 years ago

Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts

elixir [45]

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

8 0

3 years ago