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Anastasy [175]
3 years ago
6

Write a rule about the distance from the center of dilation to the vertices of the pre-image and image.

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

If A is the distance from the center of the dilation to a vertex of the pre-image, and B is the distance from the center of the dilation to the corresponding vertex on the image, then B/A is the scale factor of the dilation.

Step-by-step explanation:

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Solve for x, give exact answers: 6x^2 - 7x - 3 = 0
Novosadov [1.4K]

Answer:

Step-by-step explanation:

6x∧2-7x-3=0

the coefficient of x² multiplied by -3 = -18

we need to look for 2 numbers that when we add it to together it will equate to -7x

+2 and -9 is the answer

6x∧2+2x-9x-3=0

2x(3x+1)-3(3x+1)=0

(2x-3)(3x+1)=0

equate each brackets to 0

2x-3=0   3x+1=0

2x=3        3x=-1

x=3/2         x=-1/3

4 0
3 years ago
Read 2 more answers
If m^1=m^2 then m^ 1 is?
e-lub [12.9K]

Answer:

90

Step-by-step explanation:

5 0
3 years ago
Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.
Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

1+r = 12r²

12r²-r-1 = 0

12r²-4r+3r -1 = 0

4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or  a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of  a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0
3 years ago
6. Let f(x)=x-2 and g(x) = x^2. Find the value of (fog)(-1).<br> A. -1<br> B.9<br> C.3<br> D.-3
inna [77]

Answer:

<h2>The answer is option A</h2>

Step-by-step explanation:

f(x) = x - 2

g(x) = x²

In order to find (fog)(-1) we must first find (fog)(x)

To find (fog)(x) substitute the g(x) into f(x) that's for every x in f (x) replace it with

g (x).

That's

(fog)(x) = x² - 2

To find (fog)(-1) substitute the value of x that's - 1 into (fog)(x)

We have

(fog)(-1) = (-1)² - 2 = 1 - 2 = - 1

Hope this helps you

8 0
3 years ago
Make a box and whiskers plot of the data. average temperature in Pittsburgh in June 79,70,73,84,83,88,75,72,76,68,68,79,84,74,75
aliya0001 [1]
The box-and-whisker plot is attached.

We first order the data from least to greatest:
67,68,68,69,70,72,73,74,75,75,76,78,79,79,80,83,84,85,85,88

Now we find the median.  Since there are 20 data values, the median is between 75 and 76:
(75+76)/2 = 151/2 = 75.5

Now we find the Lower Quartile (LQ).  We do this by finding the median of the lower half of data (from the median down).  There are 10 values here; the median is between 70 and 72:
(70+72)/2 = 142/2 = 71

Find the Upper Quartile (UQ).  Do this by finding the median of the upper half of data (from the median up).  There are 10 values here; the median is between 80 and 83:
(80+83)/2 = 163/2 = 81.5

The middle bar of the box is over the median.  The left hand side of the box is over LQ, and the right hand side of the box is over UQ.  Now we draw a whisker from the box to the highest value, 88, and from the box to the lowest value, 67.

7 0
3 years ago
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