Answer:
A
Step-by-step explanation:
this is more of a mind game. Lots of words to throw you off. Daily a cow produces a mean of 6.2 gallons (average of 6.2 gallons, meaning they already found the mean, "averaged" it out for you) with a deviation of .7 gallons ("give or take" .7 gallons). On any given day (throw these words out) 68% of the cows (don't need this information to answer the question either, thrown in to confuse you) will produce an amount of milk within which of the following ranges? Just subtract the deviation ("give or take number") .7 gallons from the mean (average (already determined)) 6.2 gallons which is 5.5 gallons THEN add the deviation ("give or take number") .7 gallons to the mean (average (already determined)) 6.2 gallons which is 6.9 gallons. Your answer is A 5.5 gallons to 6.9 gallons. You don't even have to go crazy on the math on this question you can rule them all out but A immediately with subtracting .7 from 6.2. Mind games .... LOL sneaky.
Answer:
steps below
Step-by-step explanation:
3 = 2/3 m
m = 9/2
by the matrix property of associative: (A+B)+C = A+(B+C)
H = [-2 8 -1]
m x H = 9/2 x [-2 8 1] = [-9 36 -9/2]
Answer:
A. Subtract x from both sides: (i.e. 5+x-12 = x-7 <--> 5-12 = -7)
This equation is identically true, so it holds no matter what x is.
B. This one is pretty self-explanatory
Step-by-step explanation:
u wrote the question wrongly the answer is in answer box
This question also my teacher gives me
hope it helps
Answer:
0.125 = 125/1000
Step-by-step explanation:
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
---------------
A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
