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LuckyWell [14K]
3 years ago
7

(-3,9) what quadrant

Mathematics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

3

Step-by-step explanation:

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Explain how to find the estimated sum of 5/8+2/9 . Make sure to include at least one type of model.
OverLord2011 [107]
In this expression you would have to use the PEMDAS method. First divide, so (5 divided by 8) + (2 divided by 9). 
The answer you would get is: (0.625) + (0.222)
The final answer is: 0.847

8 0
3 years ago
Help me with this!
andriy [413]
Answer:
Relation #2 and #4

3 0
3 years ago
Write the perimeter of the triangle in<br> simplest form.
Genrish500 [490]

Answer:

6x +3

Step-by-step explanation:

Perimeter of a triangle is the sum of all the length of its sides. Since a triangle as 3 sides, add the 3 lengths together.

Perimeter of triangle= 2x -6 +x +8 +3x +1

<em>Bringing</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>x</em><em> </em><em>terms</em><em> </em><em>together</em><em> </em><em>and</em><em> </em><em>constants</em><em> </em><em>together</em><em>:</em>

Perimeter of triangle= 2x +x +3x -6 +8 +1

<em>Simplify:</em>

Perimeter of triangle= 6x +3

4 0
3 years ago
SOME PLEASE HELP WITH THE ANSWER!! THANK YOU
Aloiza [94]

Answer:

Geometric

Ratio = 5:1

Step-by-step explanation:

Geometric sequence is when the relation between the numbers in the sequence is multiplication or division.

For an arithmetic sequence, it is difference as it includes addition or subtraction, but since this sequence is division, we have to use ratios.

The ratio is 5:1 because the previous number is 5 times larger than the following one.

Hope this helps

8 0
3 years ago
Find the quotient. Write your answer in standard form. : 3-i/3+i
s344n2d4d5 [400]
The answer is <span>C. 4/5 - 3/5 i
</span>
\frac{3-i}{3+i} = \frac{(3-i)(3-i)}{(3+i)(3-i)} \\  \\ &#10;(a+b)(a-b) =  a^{2} -b^{2}  \\  \\ &#10;\frac{(3-i)(3-i)}{(3+i)(3-i)}= \frac{ (3-i)^{2} }{3^{2}-i^{2} } \\  \\ &#10;(a-b)^{2} =a^{2}-2ab+b^{2} \\  \\ &#10; \frac{ (3-i)^{2} }{3^{2}-i^{2} } = \frac{3^{2}-2*3*i+i^{2}  }{3^{2}-i^{2} } = \frac{9-6i+i^{2}}{9-i^{2}}  \\  \\ &#10;i =  \sqrt{-1}  \\ i^{2}=-1 \\  \\ &#10;\frac{9-6i+i^{2}}{9-i^{2}} = \frac{9-6i-1}{9+1} = \frac{8-6i}{10}= \frac{8}{10}- \frac{6i}{10}= \frac{4}{5}- \frac{3}{5}i
8 0
3 years ago
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