Hello!
Recall that:
![\sqrt[z]{x^{y} }](https://tex.z-dn.net/?f=%5Csqrt%5Bz%5D%7Bx%5E%7By%7D%20%7D)
is equal to 
. Therefore:
![\sqrt[3]{x^{2} } = x^{\frac{2}{3} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:
Answer:
4
Step-by-step explanation:
First off, integers are Whole Numbers (1,2,3,4, etc), so we are rounding the answer to the nearest whole number.
The square root of lets just say 25 means you are finding a number that multiplied by itself will equal 25 (the answer is 5).
Now for 13, there is no perfect square, however the closest whole number that multiplied by itself to 13 is 4.
4*4= 16
3*3=9
5*5=25
As you can see above 4 is the closest number to 13.
Now, the ACTUAL value of the square root of 13 is 3.60555128, but we are rounding up to the nearest whole number which is 4 :)
$70 into 1:2:4
1+2+4 = 7
7 parts= $70
1 part = $70/7 ($70 divided by 7)
1:2:4 = $10:$20:$40
answer= $10:$20:$40
Hope this helps!! :)
If it is the decimals that are giving you trouble, you can multiply both sides by 10, giving you 16k=32
To find k you divide both sides by 16
(16k)/16=(32)/16
The 16's cancel out, and the 32/16 becomes 2.
Final answer:
K=2
Answer:what is this called
Step-by-step explanation:
