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Reil [10]
3 years ago
12

Zoe says an equilateral triangle is always an acute triangle, but an acute triangle is never an equilateral triangle. Which stat

ement explains whether Zoe is correct or not?
Select one:
a. Zoe is not correct because equilateral triangles are acute triangles with three sides of equal length. Acute triangles can sometimes be equilateral triangles.

b. Zoe is not correct because equilateral triangles have three acute angles. Acute triangles have three acute angles, so acute triangles are always equilateral triangles.

c. Zoe is correct because equilateral triangles have three sides of equal length, and acute triangles have three sides of different lengths.

d. Zoe is correct because equilateral triangles have three acute angles. Acute triangles have one acute angle, so an acute triangle cannot be an equilateral triangle.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

D

Step-by-step explanation:

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3 years ago
A ball is chosen at random from a bag containing 150 balls that are either red or blue and either dull or shiny. There are 36 re
tino4ka555 [31]

Answer:

The probability of the chosen ball being shiny conditional on it being red is; 0.375

Step-by-step explanation:

Let A be the event that a red ball has been chosen

Let B be the event that a shiny ball has been chosen

Let S be the total outcomes = 150 balls

Thus;

P(A ∩ B ) = 36/150

A ∩ B' = 150 - 36 - 54

A ∩ B' = 60

Thus; P(A ∩ B') = 60/150

P(A') = 54/150

P(A) = (150 - 54)/150 = 96/150

Thus, probability of the chosen ball being shiny conditional on it being red is;

P(B | A) = P(B ∩ A)/P(A)

Thus; P(B | A) = (36/150)/(96/150)

P(B | A) = 0.375

8 0
2 years ago
The rectangle is 3 3⁄4 centimeters long and 2 1⁄2 centimeters wide. What is the area of this rectangle?
Deffense [45]
Just multiply the numers given
6 0
3 years ago
The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa
horsena [70]

Answer:

7.2 years

Step-by-step explanation:

f(t) =200(1 - 0.956e^{-0.18t})

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

148 =200(1 - 0.956e^{-0.18t})

divide both sides by 200

\frac{148}{200} = 1 - 0.956e^{-0.18t}

Now subtract 1 from both sides

-0.26= - 0.956e^{-0.18t}

Divide both sides by -0.956

\frac{0.26}{0.956} =e^{-0.18t}

Now take ln on both sides

\frac{0.26}{0.956} =e^{-0.18t}

ln(\frac{0.26}{0.956} )=-0.18tln(e)

ln(\frac{0.26}{0.956} )=-0.18t

divide both sides by -0.18

t=7.2

So 7.2 years

5 0
3 years ago
1/20 in dicimal please help
KonstantinChe [14]
0.05 is the answer for your question.
8 0
4 years ago
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