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tresset_1 [31]
3 years ago
10

At a grocery store,39 out of 60 customers use a shopping cart. What percent of the customers use a shopping cart?​

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

39 is 65% of 60

65% use a shopping cart.

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Solve. <br> | 3x + 1 | = 2
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Since this is an absolute value equation, it will have two answers. For the first answer, take away the absolute value bars and solve 3x + 1 = 2. Subtract 1 from both sides to get 3x = 1 and divide each side by 3 to get x = 1/3. Now onto the second solution. This time, take away the absolute value bars and make the other side of the equation, the 2, negative, to get 3x + 1 = -2. Now solve this by subtracting 1 from each side to get 3x = -3 and divide each side to get the other answer which is x = -1. The answer is x = -1 or 1/3, hope this helps!
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The product of 7/8 and 9/10 is greater then 9/10
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No the product will be less than 9/10.
This can be easily seen if the fractions are converted into decimals.
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4 years ago
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a meal at a restaurant cost $49.28. If the customers leave $8.23 for to determine the tip rate to the nearest whole percent. Wha
Monica [59]
Now, if the customers left 8.23 extra, based on a percentage of the cost of the meal, namely, the 8.23 is a percent of 49.28, then

if we take 49.28 to be the 100%, how much of a percentage is 8.23?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;49.28&100\\&#10;8.23&t&#10;\end{array}\implies \cfrac{49.28}{8.23}=\cfrac{100}{t}\implies t=\cfrac{8.23\cdot 100}{49.28}
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3 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
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Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

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