Since work = force * distance, the answer would 5*.5, which is 2.5 J
Answer:
The equilibrium point is at x = 6
Step-by-step explanation:
Given


Required
Determine the equilibrium point
The equilibrium point is determined by

Substitute values for Demand and Supply

Cross Multiply


Take positive square root of both sides

Hence;
<em>The equilibrium point is at x = 6</em>
Find area of room
aera=legnth wtimes width
in a square, legnth=width
aera=legnth^2
legnth=14 feet
convert o inches
14*12=168 inches
area=168^2=28224 square inches
how many tiles will cover all of floor?
aka
how many 192 in^2 is at least 28224 (at least, because we need to cover the whole floor without gaps)
192x<u>></u>28224
divide both sides by 192
x<u>></u>147
147 is the number of tiles we need
MCan you please explain more so I can give you the answer as a fraction
Answer:
Option D. 7/250 = 24.8/x; 885.71
Step-by-step explanation:
we know that
Using proportion
