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V125BC [204]
3 years ago
10

On a coordinate grid point P is at (5,8) in point are is a ( -1, -3) points Q and S are a reflection of birth points across the

Y axis. What are the coordinates of Q and S?
Mathematics
1 answer:
makkiz [27]3 years ago
8 0

Answer:

The coordinates of Q and S are;

(-5,8) and (1,-3)

Step-by-step explanation:

When we reflect a point with coordinates (x,y) across the y-axis, we get a new point with the coordinates (-x,y)

So (5,8) becomes (-5,8)

and (-1,-3) becomes (1,-3)

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Which type of reasoning allows you to use observation to find the next three values in the number pattern 1,4,7,10.....?
Mice21 [21]

Answer:

The next number in the pattern is 13.

Step-by-step explanation:

From 1, i add 3 and i get 4, then i add 3 to 4 and get 7 and then i add 3 to 7 to get 10. From here you can quickly observe that you add three to ten to get 13

3 0
3 years ago
The table represent temperatures for 9 days in February. What is the average temperature?
Artist 52 [7]

Answer:sum =378 according to your new questions.

to find average temperature

use formula

average =sum of temperature /no of measuring day

=378/9=42 is your answer

6 0
3 years ago
Number line to multiply by 2 digit number by 20
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3 years ago
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
3 years ago
Given f(x) = 3x - 5 which statement is true? Explain how.
Ann [662]

Answer:

(2)

Step-by-step explanation:

by substituting the values of x into f(x) and evaluating

f(0) = 3(0) - 5 = 0 - 5 = - 5 ≠ 0

f(3) = 3(3) - 5 = 9 - 5 = 4 ← True

f(4) = 3(4) - 5 = 12 - 5 = 7 ≠ 3

f(5) = 3(5) - 5 = 15 - 5 = 10 ≠ 0

3 0
2 years ago
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