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andre [41]
2 years ago
6

Which digit is in the trillions place in 12,345,678,900,000

Mathematics
2 answers:
zalisa [80]2 years ago
5 0

Answer:

2

Step-by-step explanation:

choli [55]2 years ago
5 0

Answer:

The answer is

→ <u><em>2</em></u>

Step-by-step explanation:

Let's look at the number.

12,345,678,900,000

And were asked to find the digit in the <u><em>trillions</em></u> place in this number.

Well, if we say it by word, then it will be:

twelve trillion, three hundred and forty-five billion, six hundred and seventy-eight million, and nine hundred thousand

Well, since were trying to find the digit in the <u><em>trillionth</em></u> place, then 12 trillion cannot be correct because the digits are in the 10 trillionth place. Ignore the 1 and you can see a number <u><em>2</em></u> in the trillionth place.

Therefore, your answer is <u><em>2.</em></u>

Hope this helped! :^)

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Hello!

The equation for a circle is

(x - h)^{2}  + ( y - k)^{2} =  r^{2}

(h,k) is the center
r is the radius

Put in the values you know

(x - 7)^{2} + ( y + 3)^{2} = 7^{2}

Simplify

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The equation is (x - 7)^{2} + ( y + 3)^{2} = 49

Hope this helps!
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Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

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Answer:The number of angles & sides is always the same.

Step-by-step explanation:

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