The expected value per game is -0.26. Over 1000 games, you can expect to lose $263.16.
To find the expected value, we multiply the probability of winning by the amount of winnings, the probability of losing by the amount of loss, and adding those together.
We have a 1/38 chance of winning; 1/38(175) = $4.61. We also have a 37/38 chance of losing; 37/38(5) = $4.87.
$4.61-$4.87 = -$0.26 (rounded)
To five decimal places, our answer is -0.26136; multiplied by 1000 games, this is $261.36 lost.
I’m not 100% sure but it could be 225 and 328. Adding those together you get a sum of 553.
Hope this helped! Mark me brainliest if you’d like, im tryna get too expert!
I would say that the answer is D 21.63
Answer: Option 3 = 4
Step-by-step explanation: f(x) = 6 - 2x
f(0) = 6 - 2(0) Range = 6
f(2) = 6 - 2(2) Range = 2
f(4) = 6 - 2(4) Range = -2
f(6) = 6 - 2(6) Range = -6
f(8) = 6 - 2(8) Range = -10
The only one that doesn't belong is 4 option 3.
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Answer:
y = 4
Step-by-step explanation:
First we want to raise -1 to the power of 2
y = 2 * 1 - 5 * -1 - 3
Multiply
2 - 5 * -1 - 3
Multiply
y = 2 + 5 - 3
y = 7 - 3
y = 4
