Answer:
2
Step-by-step explanation:
perpendicular means the opposite inverse of a slope. So -1/2 will become 2/1 or simply 2.
opposite means the sign will change, negative becomes positive and positive becomes negative.
inverse flip numerator and denominator.
Answer:
y=0x-1
Step-by-step explanation:
y=0(x)+c
-1=0(7)+c
-1=0+c
C=-1
Answer: $608.24
Step-by-step explanation:
Hi, first we have to calculate the percentage amount of the discount.
We have to multiply the cost by the sale percentage in decimal form.
703 x (16/100) =703 x 0.16 =112.48
Then, we have to subtract that amount to the original cost.
703-112.48 = 590.52
Then, we have to calculate the sale tax amount by multiplying the sale cost by the tax percentage in decimal form.
590.52 x (3/100) = 590.52 x 0.03 =17.7156
Finally adding that amount to the sale cost.
590.52 +17.7156 = $608.24
<span>A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation: x<span> + 1 = 4 </span>means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.</span><span><span>For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x<span> + 1 </span>-<span> 1 = 4 </span>-<span> 1</span>Now simplifying both sides we have:x<span> + 0 = 3</span>So:</span><span>x<span> = 3</span></span></span><span>With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.<span>Example 1, Solve for ‘x’ :</span>x<span> + 1 = </span>-31. Subtract 1 from both sides:x<span> + 1 </span>-<span> 1 = </span>-<span>3 </span>-<span> 1</span>2. Simplify both sides:x<span> = </span>-4<span>Example 2, Solve for ‘x’ :</span>-<span>2x = 12</span>1. Divide both sides by -2:2. Simplify both sides:x<span> = </span>-6<span>Example 3, Solve for ‘x’ :</span>1. Multiply both sides by 3:2. Simplify both sides:<span>x = </span>-6<span>Example 4, Solve for ‘x’ :</span><span>2x + 1 = </span>-171. Subtract 1 from both sides:<span>2x + 1 </span>-<span> 1 = </span>-<span>17 </span>-<span> 1</span>2. Simplify both sides:<span>2x = </span>-183. Divide both sides by 2:4. Simplify both sides:<span>x = </span>-9<span>Example 5, Solve for ‘x’ :</span>1. Multiply both sides by 9:2. Simplify both sides:<span>3x = 36</span>3. Divide both sides by 3:4. Simplify both sides:x = 12<span>Example 6, Solve for ‘x’ :</span> 1. Multiply both sides by 3: 2. Simplify both sides:<span> x + 1 = 21</span> 3. Subtract 1 from both sides:<span> x + 1 </span>-<span> 1 = 21 </span>-<span> 1</span> 4. Simplify both sides:x = 20<span>Example 7, Solve for ‘x’ :</span><span>7(x </span>-<span> 1) = 21</span>1. Divide both sides by 7:2. Simplify both sides:<span>x </span>-<span> 1 = 3</span>3. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 3 + 1</span>4. Simplify both sides:x = 4<span>Example 8, Solve for ‘x’ :</span>1. Multiply both sides by 5:2. Simplify both sides:<span>3(x </span>-<span> 1) = 30</span>3. Divide both sides by 3:4. Simplify both sides:<span>x </span>-<span> 1 = 10</span>5. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 10 + 1</span>6. Simplify both sides:x<span> = 11</span><span>Example 9, Solve for ‘x’ :</span><span>5x + 2 = 2x + 17</span>1. Subtract 2x from both sides:<span>5x + 2 </span>-<span> 2x = 2x + 17 </span>-<span> 2x</span>2. Simplify both sides:<span>3x + 2 = 17</span>3. Subtract 2 from both sides:<span>3x + 2 </span>-<span> 2 = 17 </span>-<span> 2</span>4. Simplify both sides:<span>3x = 15</span>5. Divide both sides by 3:6. Simplify both sides:x = 5<span>Example 10, Solve for ‘x’ :</span><span>5(x </span>-<span> 4) = 3x + 2</span>1. Expand brackets:<span>5x </span>-<span> 20 = 3x + 2</span>2. Subtract 3x from both sides:<span>5x </span>-<span> 20 </span>-<span> 3x = 3x + 2 </span>-<span> 3x</span>3. Simplify both sides:<span>2x </span>-<span> 20 = 2</span>4. Add 20 to both sides:<span>2x </span>-<span> 20 + 20 = 2 + 20</span>5. Simplify both sides:<span>2x = 22</span>6. Divide both sides by 2:7. Simplify both sides:x <span>= 11</span></span>
