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irina1246 [14]
3 years ago
11

What number x makes the equation 8 to the power of x = 2 correct?

Mathematics
2 answers:
azamat3 years ago
7 0
Yes, because if you multiply 2*2*2=8 so yes you're right.....
Daniel [21]3 years ago
6 0
<span>A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation:  x<span> + 1 = 4 </span>means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.</span><span><span>For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x<span> + 1 </span>-<span> 1 = 4 </span>-<span> 1</span>Now simplifying both sides we have:x<span> + 0  = 3</span>So:</span><span>x<span>  = 3</span></span></span><span>With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.<span>Example 1, Solve for ‘x’ :</span>x<span> + 1  =   </span>-31. Subtract 1 from both sides:x<span> + 1 </span>-<span> 1 =   </span>-<span>3 </span>-<span> 1</span>2. Simplify both sides:x<span>   =   </span>-4<span>Example 2, Solve for ‘x’ :</span>-<span>2x   =   12</span>1. Divide both sides by -2:2. Simplify both sides:x<span>   =   </span>-6<span>Example 3, Solve for ‘x’ :</span>1. Multiply both sides by 3:2. Simplify both sides:<span>x   =   </span>-6<span>Example 4, Solve for ‘x’ :</span><span>2x + 1  =  </span>-171. Subtract 1 from both sides:<span>2x + 1 </span>-<span> 1  =  </span>-<span>17 </span>-<span> 1</span>2. Simplify both sides:<span>2x  =  </span>-183. Divide both sides by 2:4. Simplify both sides:<span>x   =   </span>-9<span>Example 5, Solve for ‘x’ :</span>1. Multiply both sides by 9:2. Simplify both sides:<span>3x   =   36</span>3. Divide both sides by 3:4. Simplify both sides:x   =   12<span>Example 6, Solve for ‘x’ :</span>  1. Multiply both sides by 3:  2. Simplify both sides:<span> x + 1   =   21</span>  3. Subtract 1 from both sides:<span> x + 1 </span>-<span> 1 =   21 </span>-<span> 1</span>  4. Simplify both sides:x   =   20<span>Example 7, Solve for ‘x’ :</span><span>7(x </span>-<span> 1)  =  21</span>1. Divide both sides by 7:2. Simplify both sides:<span>x </span>-<span> 1   =   3</span>3. Add 1 to both sides:<span>x </span>-<span> 1 + 1 =   3 + 1</span>4. Simplify both sides:x   =   4<span>Example 8, Solve for ‘x’ :</span>1. Multiply both sides by 5:2. Simplify both sides:<span>3(x </span>-<span> 1)   =   30</span>3. Divide both sides by 3:4. Simplify both sides:<span>x </span>-<span> 1   =   10</span>5. Add 1 to both sides:<span>x </span>-<span> 1 + 1 =   10 + 1</span>6. Simplify both sides:x<span>   =   11</span><span>Example 9, Solve for ‘x’ :</span><span>5x + 2  =  2x + 17</span>1. Subtract 2x from both sides:<span>5x + 2 </span>-<span> 2x =   2x + 17 </span>-<span> 2x</span>2. Simplify both sides:<span>3x + 2   =   17</span>3. Subtract 2 from both sides:<span>3x + 2 </span>-<span> 2 =   17 </span>-<span> 2</span>4. Simplify both sides:<span>3x   =   15</span>5. Divide both sides by 3:6. Simplify both sides:x   =   5<span>Example 10, Solve for ‘x’ :</span><span>5(x </span>-<span> 4)  =  3x + 2</span>1. Expand brackets:<span>5x </span>-<span> 20   =   3x + 2</span>2. Subtract 3x from both sides:<span>5x </span>-<span> 20 </span>-<span> 3x =   3x + 2 </span>-<span> 3x</span>3. Simplify both sides:<span>2x </span>-<span> 20   =   2</span>4. Add 20 to both sides:<span>2x </span>-<span> 20 + 20 =   2 + 20</span>5. Simplify both sides:<span>2x   =   22</span>6. Divide both sides by 2:7. Simplify both sides:x   <span>=   11</span></span>
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A circle has an area of 50 square meters. Which answer is closest to the measure of its diameter?
gregori [183]
Area of a circle is computed by multiplying pi to the square of the circle's radius.

A = πr²
50m² = 3.14 r²
50m²/3.14 = r²
r² = 15.92m²
r = √15.92m²
r = 3.99m

Diameter is computed by multiplying the radius twice.
d = 2r
d = 2(3.99m)
d = 7.98m or rounded up to 8 m
8 0
3 years ago
What is 5+7?<br><br> I literally will give the highest amount of points
Dovator [93]

5 + 7 is equal to 12. Is this kindergarten math?

4 0
3 years ago
Jessica bought a $30 outfit for $17. What percent discount did she receive?
mihalych1998 [28]
<h2>Answer:</h2>

Around 57%

<h3><u>Step-by-step explanation:</u></h3>

17 / 30 = .56666666...

Move two decimal places to the left;

56.66666...

<em>Estimate:</em> 57%

8 0
3 years ago
Read 2 more answers
Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]
Leni [432]

Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

f(x)=\dfrac{2x-1}{2}

We need to find the average value of the function on the given interval [1,13].

f(x)=\dfrac{2x}{2}-\dfrac{1}{2}

f(x)=x-0.5

The average value of the function f(x) on [a,b] is

Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx

Average value of the function on the given interval [1,13] is

Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx

Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}

Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]

Average=\dfrac{1}{12}[78-0]

Average=6.5

Therefore, the average value of the function on the given interval 6.5.

6 0
3 years ago
i need help with number 2 on left side i dont need to find out what x is i need to figure out what degrees each corner is to equ
Aloiza [94]
So what is the question
5 0
3 years ago
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