Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
The distance between the ground and the kite to the nearest foot is 64 ft.
<h3>What is a right angle triangle?</h3>
A right angle triangle is a triangle that has one of its sides as 90 degrees. The situation forms a right angle triangle.
Hence,
The length of the kite string is the hypotenuse side of the triangle formed.
The height between the ground and the kite is the opposite side of the triangle formed.
Therefore, using trigonometric ratio,
sin 40 = opposite / hypotenuse
sin 40 = h / 100
cross multiply
h = 100 sin 40
h = 100 × 0.64278760968
h = 64.2787609687
h = 64 ft
Therefore, the distance between the ground and the kite to the nearest foot is 64 ft.
learn more on right triangle here: brainly.com/question/27482803
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Answer:
Step-by-step explanation:
You have to use the triangle inequality theorem:
12cm, 4cm, xcm
x > 4cm - 12cm
x > -8cm
x < 12cm - 4cm
x < 8cm
-8cm < x < 8cm
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer:
Solve the equation for y by finding a, b, and c
of the quadratic then applying the quadratic formula.
Exact Form:
y = 3,−9/2
Decimal Form:
y = 3,−4.5
Mixed Number Form:
y = 3,− 4 1/2
Step-by-step explanation:
branliest pls
