Answer: In your problem, you said that they are squared. However, it is not written as squared. We just have to multiply them.
We can use the FOIL method.
(3b - 5c)(3x + 5y)
6bx + 15by - 10cx - 25cy
There are no like terms, so that expression is our final answer.
Answer:
no to both questions, they might numb your gums but im not 100% sure.
Step-by-step explanation:
Idk if this will help, but her :)
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
