I need help on how to solve ( x2-5x-12) ÷ (x+3)

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

x - 8 + $\frac{12}{x+3}$

Step-by-step explanation:

One way to do the division is to use the divisor as a factor in the numerator

Consider the numerator

x(x + 3) - 3x - 5x - 12

= x(x + 3) - 8(x + 3) + 24 - 12

= x(x + 3) - 8(x + 3) + 12

quotient = x - 8 and remainder = 12

$\frac{x^2-5x-12}{x+3}$ = x - 8 + $\frac{12}{x+3}$

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