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3 years ago

6

I need help on how to solve ( x2-5x-12) ÷ (x+3)

1 answer:

HACTEHA [7]3 years ago

4 0

Answer:

x - 8 + $\frac{12}{x+3}$

Step-by-step explanation:

One way to do the division is to use the divisor as a factor in the numerator

Consider the numerator

x(x + 3) - 3x - 5x - 12

= x(x + 3) - 8(x + 3) + 24 - 12

= x(x + 3) - 8(x + 3) + 12

quotient = x - 8 and remainder = 12

$\frac{x^2-5x-12}{x+3}$ = x - 8 + $\frac{12}{x+3}$

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_x(-26) = 26 what is the first part

Aliun [14]

Answer:

-

Step-by-step explanation:

Two negatives create a positive.

6 0

3 years ago

Read 2 more answers

Evaluate the expression below using the properties of operations. Show your steps.−36 ÷ 14 ⋅ (−18) ⋅ (−3) ÷ 6

s2008m [1.1K]

Answer:

(-162)/7 or -23 1/7 as mixed fraction

Step-by-step explanation:

Simplify the following:

(-36)/14 (-18) (-3)/6

Hint: | Express (-36)/14 (-18) (-3)/6 as a single fraction.

(-36)/14 (-18) (-3)/6 = (-36 (-18) (-3))/(14×6):

(-36 (-18) (-3))/(14×6)

Hint: | In (-36 (-18) (-3))/(14×6), divide -18 in the numerator by 6 in the denominator.

(-18)/6 = (6 (-3))/6 = -3:

(-36-3 (-3))/14

Hint: | In (-36 (-3) (-3))/14, the numbers -36 in the numerator and 14 in the denominator have gcd greater than one.

The gcd of -36 and 14 is 2, so (-36 (-3) (-3))/14 = ((2 (-18)) (-3) (-3))/(2×7) = 2/2×(-18 (-3) (-3))/7 = (-18 (-3) (-3))/7:

(-18 (-3) (-3))/7

Hint: | Multiply -18 and -3 together.

-18 (-3) = 54:

(54 (-3))/7

Hint: | Multiply 54 and -3 together.

54 (-3) = -162:

Answer: (-162)/7

3 0

3 years ago

Place an operation sign between two of the digits to make the equation true

I am Lyosha [343]

An addition sign between 978 and 842 would make the equation true!

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=make%20x%20the%20subject%20of%20formula%20in%20the%20equation%204a%5Csqrt%7Bx%7D%20%3D%5Cfrac%

kipiarov [429]

Answer: $x = (\frac{1}{4ab})^{2}$

Step-by-step explanation:

Given:

$4a\sqrt{x} = \frac{1}{b}$

To make $x$ the subject of the formula means that we want to make $x$ to stand alone , the first thing to do is to multiply through by 1/4a , that is

$\sqrt{x} = \frac{1}{4ab}$

take the square of both sides:

$x = (\frac{1}{4ab})^{2}$

3 0

3 years ago

Read 2 more answers

Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of

victus00 [196]

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

In this case:

$(a,b) = (0,3)$

i.e.

$a = 0\\b=3$

For f(x)

$f(x) = 16(\frac{1}{2})^x$

$Rate = \frac{f(b) - f(a)}{b - a}$

$Rate = \frac{f(3) - f(0)}{3 - 0}$

$Rate = \frac{f(3) - f(0)}{3}$

Calculate f(3) and f(0)

$f(x) = 16(\frac{1}{2})^x$

$f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2$

$f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16$

So:

$Rate = \frac{f(3) - f(0)}{3}$

$Rate = \frac{2 - 16}{3}$

$Rate = -\frac{14}{3}$

For g(x)

$Rate = \frac{g(b) - g(a)}{b - a}$

$Rate = \frac{g(3) - g(0)}{3 - 0}$

$Rate = \frac{g(3) - g(0)}{3}$

From the table of g(x)

$g(3) = 1$

$g(1) = 27$

So:

$Rate = \frac{1 - 27}{3}$

$Rate = -\frac{26}{3}$

For h(x)

$Rate = \frac{h(b) - h(a)}{b - a}$

$Rate = \frac{h(3) - h(0)}{3 - 0}$

$Rate = \frac{h(3) - h(0)}{3}$

From the graph of h(x)

$h(3) = -3$

$h(0) = 4$

So:

$Rate = \frac{-3 - 4}{3}$

$Rate = -\frac{7}{3}$

So, the calculated rates of change are:

$f(x) = -\frac{14}{3}$ $= -4.67$

$g(x) = -\frac{26}{3}$ $=-8.67$

$h(x) = -\frac{7}{3}$ $=-2.33$

By comparison:

From the fastest decreasing to slowest, the order is: <em>g(x), f(x) and h(x)</em>

4 0

3 years ago