The Semi-Major Axis is half the longest diameter of the ellipse and the Eccentricity gives the shape of the ellipse.
Answer:
The answer is 754.4 cm²
Step-by-step explanation:
a = r²π
a = (31/2)²π
a ≈ 754.4
2a
3c
4b
Cross multiply for 2
Put 4x-5=3x-10 and subtract 3 on both sides. After that add 10 to both sides for 3
Divide everything by 5 and multiply everything by -2 for 4
23m. Simply add the coefficients and the m stays the same
Answer:
![\boxed{\sf \frac{15}{22} }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5Cfrac%7B15%7D%7B22%7D%20%7D)
Step-by-step explanation:
The radius of the circle is 7 cm.
The two legs of the triangles are 7cm as well.
Area of a trinagle is ( base × height )/2.
![\frac{7 \times 7}{2} =24.5](https://tex.z-dn.net/?f=%5Cfrac%7B7%20%5Ctimes%207%7D%7B2%7D%20%3D24.5)
Multiply the value by 2 since there are two triangles.
![24.5 \times 2 = 49](https://tex.z-dn.net/?f=24.5%20%5Ctimes%202%20%3D%2049)
Calculate the area of the circle.
![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
The radius is given.
![\pi (7)^2](https://tex.z-dn.net/?f=%5Cpi%20%287%29%5E2)
Take
as ![\frac{22}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B22%7D%7B7%7D)
![49(\frac{22}{7} )](https://tex.z-dn.net/?f=49%28%5Cfrac%7B22%7D%7B7%7D%20%29)
![=154](https://tex.z-dn.net/?f=%3D154)
Subtract the area of the two triangles from the area of the whole circle.
![154-49=105](https://tex.z-dn.net/?f=154-49%3D105)
The area of the shaded part is 105 cm². The total area of the shape is 154cm².
![\frac{105}{154} =\frac{15}{22}](https://tex.z-dn.net/?f=%5Cfrac%7B105%7D%7B154%7D%20%3D%5Cfrac%7B15%7D%7B22%7D)