Answer:
One number is 4.2, the other is 18.8
Step-by-step explanation:
1.) x+y=23
(x+6y)x2=4
2.) (x+6y)x2=4 = 2x+12y=4
3.)Use elimination/substitution to solve
2x+12y=4 = x+6y=2 = x=2-6y
2-6y+y=23
4.)Solve for y
2-5y=23 -> -5y=21 -> y=4.2.
5.)Solve for x
x+4.2=23
x=18.8
I may be wrong so let me know if I am
4.
This is because 4 goes into 16 4 times, hence 4 x 4 being 16.
Therefore, the answer would be four.
Hope this helps!
Answer: 20
Step-by-step explanation:
Answer:
36.01% probability that there will be 4 failures.
Step-by-step explanation:
A sequence of Bernoulli trials is the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
In this problem, we have that:
![n = 5, p = 0.3](https://tex.z-dn.net/?f=n%20%3D%205%2C%20p%20%3D%200.3)
a. In five Bernoulli trials, what is the probability that there will be 4 failures?
This is 4 failures and 5-4 = 1 success
This is P(X = 1).
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{4} = 0.3601](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B5%2C1%7D.%280.3%29%5E%7B1%7D.%280.7%29%5E%7B4%7D%20%3D%200.3601)
36.01% probability that there will be 4 failures.
Answer:1800
Step-by-step explanation:12000x5%=600x3=1800