8k-4k+4+7-k =
8k-4k-k+4+7 =
3k+11
Answer:
28
Step-by-step explanation:
5(6) + (-2) = 30 + (-2) = 30-2 = 28
9514 1404 393
Explanation:
<h3>8.</h3>
An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.
The above relation tells us ...
∠PRS = ∠PQR +∠QPR = 2q +2p
Then ...
∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p
and
∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior
q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR
p = ∠QTR = 1/2(∠QPR) . . . . . subtract q
__
<h3>9.</h3>
For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...
∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°
Substituting the congruent angles, this gives ...
∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation
Answer:
15
Step-by-step explanation:
3x3=9
so therefore you need to multiply 2 by 3=6
9+6=15
The linear function that maps the relation between kinetic energy and mass is given at the end of the question.
<h3>What is the kinetic energy of an object?</h3>
The kinetic energy of an object is given by the following formula:
E = 0.5mv².
In which:
- m is the mass of the object.
- v is the velocity of the object.
In this problem, we suppose a velocity of 2.5 m/s, hence the kinetic energy is:
E = 0.5m(2.5)² = 3.125m.
Hence the graph is plotted at the end of the answer.
More can be learned about kinetic energy at brainly.com/question/25959744
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