The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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Answer:
A: 1/5
B: 3/5
Step-by-step explanation:
The least common multiple is 2
X=Y-7
4X+2Y=62
4(Y-7)+2Y=62
4Y-28+2Y=62
6Y=62+28
6Y=90
Y=90/6
Y=15
Larger number^
X=15-7=8
Smaller number^
PROOF:
4*8+2*15=62
32+30=62
62=62
Hope this helps.
12y +6 is the answer to that question