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3 years ago

What is 70 in standard form?

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

Answer:

$7 \times {10}^{2}$

<h2>HOPE IT HELPS YOU ✌️</h2>

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The distance on the map between Yappy city and Quiet city is 23 cm.

jekas [21]

The actual distance between Yappy city and Quiet city when it is 23 cm in map is 9.2 miles.

What is scaling ?

It is the technique to resize drawing with comparing to actual size of object which uses proportion or ratio. For example, Mapping of earth, drawing prototype of automobiles.

It is given that :

The distance on the map between Yappy city and Quiet city is 23 cm

and,

5cm = 2 miles

now, for 1 cm on map it is equal to 2/5 miles of actual distance.

Therefore to find the actual distance of 23 cm in map we simply multiply 23 with 2/5 :

actual distance :

2/5 x 23 = 9.2 miles

Therefore, the actual distance between Yappy city and Quiet city is 9.2 miles.

Read more about ratio at:

brainly.com/question/17869111

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1 year ago

Please help! Find the measure of the angle labeled with the question mark.

zmey [24]

Answer:

it is 125°

Step-by-step explanation:

alternate interior angles are equal

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3 years ago

Please help, this is due today!

mrs_skeptik [129]

Answer: The moon was 20 farms away from earth so If I ate a couch then went to my treadmill outside of my cow, I could add the letter Grammar to my checklist.

Explanation: You see, If there was a man who had no arms or legs he would be walking with his feet right? SO If I added chickens to my head and ate the Eifel tower am I 50% a chocolate bar. Hope this helps

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3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba

katovenus [111]

The lower end of the range is
42.670 - 0.002 = 42.668 mm

The upper end of the range is
42.670 + 0.002 = 42.672 mm

The range of acceptable values is 42.668 mm to 42.672 mm.

6 0

3 years ago

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What is 70 in standard form?​

What is 70 in standard form?