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3 years ago

Rewrite in radical form

Mathematics

2 answers:

Marianna [84]3 years ago

5 0

Answer:

6 1/3

Step-by-step explanation:

tresset_1 [31]3 years ago

5 0

Can you help with my questions please

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How do you write ten fifteens in the simplest form for fraction

kirza4 [7]

10/15 divided by 5 = 5/10

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3 years ago

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Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

Need help ASAPPPPPPP

patriot [66]

Answer:

8 is the correct answer because coefficient lies before Exponent. Exponent is variable

So 8 is the coefficient.

5 0

2 years ago

6. Jessie sorted the coins in her bank. Shemade 7 stacks of 6 dimes and 8 stacksof 5 nickels. She then found 1 dime and1 nickel.

Leokris [45]

Lets write down the information that we know.

Jessie has 7 stacks of 6 dimes, so Jessie has a total of 6*7 dimes

Dimes=7*6=42dimes

Jessie has 42 dimes, but then she found another one so lets add one more dime.

42+1=43 dimes

Jessie has 8 stacks of 5 nickels, so Jessie has 8*5 nickels

Nickels=8*5=40nickels

Jessie has 40 nickels, but then she found another one so lets add 1 to the total number of nickels.

40+1=41nickels

Now we can answer the question.

How many dimes and nickels does jessie have in all?

nickels+dimes=
41+43=84 coins

Jessie has 84 coins in total

3 0

3 years ago

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Ten million more than 280,509,031

Maru [420]

That means you are multipliying 10,000,000 by 280,509,031...

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3 years ago

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